Physics

# "Impulse per unit area" has same dimensions as that of

coefficient of viscosity

##### SOLUTION
Impulse per unit area $\displaystyle = \frac{f\times t}{L^{2}} = \frac{M^{1} L^{1} T^{-2}\times T^{1}}{L^{2}} =M^{1} L^{-1} T^{-1}$

Coeff. of viscosity $= M^{1} L^{-1} T^{-1}$

Surface Tension $= \dfrac{f}{l} = \dfrac{M^{1} L^{1} T^{-2}}{L} = MT^{-2}$

Bulk Modulus $= \dfrac{dp}{\dfrac{dv}{v}} = M^{1} L^{-1} T^{-2}$

Gravitational poential $\displaystyle = \frac{GM}{r} = \frac{foru\times r}{Mass} = \frac{M^{1} L^{1} T^{-2}\times L^{1}}{M^{1}} = L^{2} T^{-2}$

Hence, option A is correct.

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Single Correct Medium Published on 18th 08, 2020
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