Physics

"Impulse per unit area" has same dimensions as that of


ANSWER

coefficient of viscosity


SOLUTION
Impulse per unit area $$\displaystyle = \frac{f\times t}{L^{2}} = \frac{M^{1} L^{1} T^{-2}\times T^{1}}{L^{2}} =M^{1} L^{-1} T^{-1}$$

Coeff. of viscosity $$= M^{1} L^{-1} T^{-1}$$

Surface Tension $$= \dfrac{f}{l} = \dfrac{M^{1} L^{1} T^{-2}}{L} = MT^{-2}$$

Bulk Modulus $$= \dfrac{dp}{\dfrac{dv}{v}} = M^{1} L^{-1} T^{-2}$$

Gravitational poential $$\displaystyle = \frac{GM}{r} = \frac{foru\times r}{Mass} = \frac{M^{1} L^{1} T^{-2}\times L^{1}}{M^{1}} = L^{2} T^{-2}$$

Hence, option A is correct.
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