Physics

A particle of mass $$m$$ is in a uni-directional potential field where the potential energy of a particle depends on the x-coordinate given by $$\phi_x=\phi_0(1-cos\;ax)$$ & $$'\phi_0'$$ and $$'a'$$ are constants. Find the physical dimensions of $$'a'$$ & $$\phi_0$$.


ANSWER

$$L^{-1},\;M^1L^2T^{-2}$$


SOLUTION

Dimensions of $$ax=M^{\circ}L^{\circ}T^{\circ}$$

$$\Rightarrow [a]=\displaystyle\frac{M^{\circ}L^{\circ}T^{\circ}}{[L]}=L^{-1}\;and\;[\phi_0]=[M^1L^2T^{-2}]$$

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Single Correct Medium Published on 18th 08, 2020
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