Physics

# A particle of mass $m$ is in a uni-directional potential field where the potential energy of a particle depends on the x-coordinate given by $\phi_x=\phi_0(1-cos\;ax)$ & $'\phi_0'$ and $'a'$ are constants. Find the physical dimensions of $'a'$ & $\phi_0$.

$L^{-1},\;M^1L^2T^{-2}$

##### SOLUTION

Dimensions of $ax=M^{\circ}L^{\circ}T^{\circ}$

$\Rightarrow [a]=\displaystyle\frac{M^{\circ}L^{\circ}T^{\circ}}{[L]}=L^{-1}\;and\;[\phi_0]=[M^1L^2T^{-2}]$

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Single Correct Medium Published on 18th 08, 2020
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