Mathematics

A ray $OC$ stands on a line $AOB$. Find $x$ if $\angle AOC=x+20^{o}$ and $\angle BOC=3x-8^{o}$.

SOLUTION
$\begin{array}{l} From\, the\, figure\, we\, get \\ \angle AOC+\angle BOC={ 180^{ \circ } } \\ \Rightarrow x+{ 20^{ \circ } }+3x-{ 8^{ \circ } }={ 180^{ \circ } } \\ \Rightarrow 4x={ 180^{ \circ } }-{ 12^{ \circ } } \\ \Rightarrow x=\dfrac { { { { 168 }^{ \circ } } } }{ 4 } \\ \therefore x={ 42^{ \circ } } \\ hence,\, the\, \, value\, of\, x\, is\, { 42^{ \circ } }. \end{array}$ You're just one step away

Subjective Medium Published on 09th 09, 2020
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