Mathematics

A ray $$OC$$ stands on a line $$AOB$$. Find $$x$$ if $$\angle AOC=x+20^{o}$$ and $$\angle BOC=3x-8^{o}$$.


SOLUTION
$$\begin{array}{l} From\, the\, figure\, we\, get \\ \angle AOC+\angle BOC={ 180^{ \circ  } } \\ \Rightarrow x+{ 20^{ \circ  } }+3x-{ 8^{ \circ  } }={ 180^{ \circ  } } \\ \Rightarrow 4x={ 180^{ \circ  } }-{ 12^{ \circ  } } \\ \Rightarrow x=\dfrac { { { { 168 }^{ \circ  } } } }{ 4 }  \\ \therefore x={ 42^{ \circ  } } \\ hence,\, the\, \, value\, of\, x\, is\, { 42^{ \circ  } }. \end{array}$$
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Subjective Medium Published on 09th 09, 2020
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