Mathematics

An angle is $$14^{o}$$ more than its complementary angle. What is the measure?


SOLUTION

Let first angle is $$={{x}^{o}}$$

Then, IInd angle is $$=x+{{14}^{o}}$$

According to given question,

$$ x+x+14={{90}^{o}} $$

$$ 2x={{90}^{o}}-{{14}^{o}} $$

$$ 2x={{76}^{o}} $$

$$ x={{38}^{o}} $$

Then, IInd angle is $$x+{{14}^{o}}={{38}^{o}}+{{14}^{o}}={{52}^{o}}$$


Hence, this is the answer.
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