Mathematics

An angle is $$\dfrac {2}{3}$$ of its supplementary. What is its magnitude?


SOLUTION
$$\Rightarrow$$  Let one angle be $$x$$.
$$\Rightarrow$$  Then, other angle will be $$\dfrac{2}{3}x$$
According to the question,
$$x+\dfrac{2}{3}x=180^o$$
$$\dfrac{3x+2x}{3}=180^o$$
$$\dfrac{5x}{3}=180^o$$
$$5x=540^o$$
$$\therefore$$   $$x=108^o$$
$$\therefore$$  $$\dfrac 23 x=\ \dfrac{2}{3} \times 108^o=72^o$$
$$\therefore$$  Magnitudes are $$108^o$$ and $$72^o$$
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