Physics

Current "$$I$$" flows through an inductive circuit. The work done is equal to  $$\dfrac{{ LI }^{ 2 }}{2}$$. The dimensions of work done is:


ANSWER

$${ ML }^{ 2 }{ T }^{ -2 }$$


SOLUTION
Energy stored by an inductor is given by $$\dfrac{1}{2}{LI}^2$$.
Thus the dimension of $${LI}^2$$ is of energy only. $$\Rightarrow ML^2T^{-2}$$
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Single Correct Medium Published on 18th 08, 2020
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