Physics

# Current "$I$" flows through an inductive circuit. The work done is equal to  $\dfrac{{ LI }^{ 2 }}{2}$. The dimensions of work done is:

${ ML }^{ 2 }{ T }^{ -2 }$

##### SOLUTION
Energy stored by an inductor is given by $\dfrac{1}{2}{LI}^2$.
Thus the dimension of ${LI}^2$ is of energy only. $\Rightarrow ML^2T^{-2}$

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Single Correct Medium Published on 18th 08, 2020
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