Physics

# Dimensional formula of magnetic field of induction (B) is:Given Force on a charged particle is given by: $F = qvBsin \theta$ where $\theta$ is angle between velocity and magnetic field.

$MT^{-2}I^{-1}$

##### SOLUTION
It is given:
$F=qvBsin \theta$
Hence, $B= \dfrac{F}{qvsin\theta}$
Dimensional formula of magnetic field is:
$[B] = [F/qv]$ as $sin \theta$ is dimensionless
$[B] = [MLT^{-2}][I^{-1}T^{-1}][L^{-1}T]$
$[B] = [MT^{-2}I^{-1}]$

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