Physics

# Dimensions of '$ohm$' are same as that of:(Given : $h$ is Planck's constant and $e$ is charge)

$\dfrac { h }{ { e }^{ 2 } }$

##### SOLUTION
$a = ohm = ML^{2}I^{-2}T^{-3}$
$b = h = ML^{2}T^{-1}$
$c = e = I^{1}T^{1}$
$a = b^{\alpha } c^{\beta }$
$ML^{2}I^{-2}T^{-3} = (ML^{2}T^{-1})^{\alpha } (I^{1}T^{1})^{\beta}$
$\Rightarrow \beta = -2, \alpha = 1$
$\Rightarrow ohm = \dfrac{h}{e^{2}}$

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Single Correct Medium Published on 18th 08, 2020
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