Physics

# Dimensions of $\dfrac { 1 }{ { \mu }_{ 0 }{ \epsilon }_{ 0 } }$ , where symbols have their usual meaning are :

${ L }^{ 2 }{ T }^{ -2 }$

##### SOLUTION
$\mu _{0}=N/A^{2}$
$E _{0}=c^{2}/Nm^{2}$
$\dfrac{1}{\mu _{0} E_{0}}=\dfrac{1}{N/A^{2}\times c^{2}/Nm^{2}}=\dfrac{m^{2}}{\dfrac{A^{2}T^{2}}{A^{2}}}=L^{2}T^{-2}$
C$\rightarrow$charge
A
$\rightarrow$current
T$\rightarrow$Time

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Single Correct Medium Published on 18th 08, 2020
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