Physics

Distance traveled by a particle at any instant '$$t$$' can be represented as $$S=A(t+B)+Ct^2$$. The dimensions of $$B$$ are


ANSWER

$$[M^0L^0T^{1}]$$


SOLUTION
In $$S=A(t+B)+Ct^2$$; B is added to time t. 
Therefore, dimensions of B are those of time $$=[M^0L^0T^{1}]$$.
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