Mathematics

# Equation of the line passing through the point of intersection of the lines $2x+3y-5=0, 3x+2y-5=0$ and having slope $-1$ is

##### SOLUTION

We have

Equation of lines

$2x+3y-5=0\ ......\ \ (1)$

$3x+2y-5=0\ \ ......\ \ (2)$

On solving equation $(1)$ and  $(2)$ to,

$(x,\ y)\$=$\ (4,\ 1)$

Let the intersection point

$(x_1,\ y_1)$$\ =$$\ (4,\ 1)$

Given that

The slope of line $(m)\ =\ -1$

So,

Equation of line

$y-{{y}_{1}}=m(x-{{x}_{1}})$

$y-1=-1(x-4)$

$y-1=-x+4$

$x+y-5=0$

You're just one step away

Subjective Medium Published on 09th 09, 2020
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