Mathematics

# Find $\angle APB$, if $AE || BR$.

##### SOLUTION
given $AE\parallel BR$
Now AB acts as transversal.
$\angle A+\angle B=180^{\circ}$ (interior angles of same side of transversal are supplementary )
$\therefore 2x+2y=180^{\circ}$
$2(x+y)=180^{\circ}$
$x+y=90^{\circ}$
Now in $\Delta APB$
$\angle PAB+\angle PBA+\angle APB=180^{\circ}$
$X+Y+\angle APB=180^{\circ}$
But $x+y=90^{\circ}$
$\therefore \angle APB=180^{\circ}-(x+y)$
$\angle APB=180^{\circ}-90^{\circ}$
$\angle APB=90^{\circ}$

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Subjective Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
Enrolled Students 86

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