Mathematics

# Find the angle which is $56^o$ more than its complement

$73$

##### SOLUTION
Let the required angle be $x$, then its complement $=(90-x)\quad$
Given that $x=(90-x)+56$
$\Rightarrow 2x=146\\ \Rightarrow x={ 73 }^{ o }\\$

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Single Correct Medium Published on 09th 09, 2020
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