Mathematics

Find the angle whose complement is itself.


SOLUTION
Let the measure of an angle be $${x}^{\circ}$$, then the measure of its complement is also $${x}^{\circ}$$

We know that the sum of the measures of an angle and it's complementary is $${90}^{\circ}$$

$$\therefore {x}^{\circ}+{x}^{\circ}={90}^{\circ}$$

$$\Rightarrow 2{x}^{\circ}={90}^{\circ}$$

$$\Rightarrow {x}^{\circ}=\dfrac{{90}^{\circ}}{2}={45}^{\circ}$$
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Subjective Medium Published on 09th 09, 2020
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