Mathematics

Find the angle whose complement is itself.

SOLUTION
Let the measure of an angle be ${x}^{\circ}$, then the measure of its complement is also ${x}^{\circ}$

We know that the sum of the measures of an angle and it's complementary is ${90}^{\circ}$

$\therefore {x}^{\circ}+{x}^{\circ}={90}^{\circ}$

$\Rightarrow 2{x}^{\circ}={90}^{\circ}$

$\Rightarrow {x}^{\circ}=\dfrac{{90}^{\circ}}{2}={45}^{\circ}$

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Subjective Medium Published on 09th 09, 2020
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