Mathematics

# Find the supplementary of $37^028'$ and $52^0 33'$.

##### SOLUTION
$For\quad an\quad angle\quad to\quad be\quad supplementary,the\quad sum\quad of\quad two\quad angles\quad should\quad be{ 90 }^{ \circ }.$
$Supplementary\quad of\quad { 37 }^{ \circ }{ 28 }^{ ' }=90-{ 37 }^{ \circ }{ 28 }^{ ' }={ 52 }^{ \circ }{ 32 }^{ ' }$
$Supplementary\quad of\quad { 52 }^{ \circ }{ 33 }^{ ' }=90-{ 52 }^{ \circ }{ 33 }^{ ' }={ 37 }^{ \circ }27^{ ' }$

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Subjective Medium Published on 09th 09, 2020
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