Mathematics

Find the supplementary of $$37^028' $$ and $$52^0 33'$$.


SOLUTION
$$For\quad an\quad angle\quad to\quad be\quad supplementary,the\quad sum\quad of\quad two\quad angles\quad should\quad be{ 90 }^{ \circ  }.$$
$$ Supplementary\quad of\quad { 37 }^{ \circ  }{ 28 }^{ ' }=90-{ 37 }^{ \circ  }{ 28 }^{ ' }={ 52 }^{ \circ  }{ 32 }^{ ' }$$
$$ Supplementary\quad of\quad { 52 }^{ \circ  }{ 33 }^{ ' }=90-{ 52 }^{ \circ  }{ 33 }^{ ' }={ 37 }^{ \circ  }27^{ ' }$$
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Subjective Medium Published on 09th 09, 2020
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