Mathematics

Find the value of the unknown exterior angle x in the following diagram.


SOLUTION
Sum of all angles of a $$\Delta le = 180^o$$
$$50^o + 50^o + \angle ACB = 180^o$$
$$\therefore \angle ACB = 80^o$$
Now, $$x + \angle ACB = 180^o$$
$$\therefore x = 100^o$$

$$Or$$
Since, Exterior angle$$=$$Sum of interior opposite angles, therefore $$x=50^o+50^o=110^o$$.
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