Mathematics

# Find the value of the unknown exterior angle x in the following diagram.

##### SOLUTION
Sum of all angles of a $\Delta le = 180^o$
$50^o + 50^o + \angle ACB = 180^o$
$\therefore \angle ACB = 80^o$
Now, $x + \angle ACB = 180^o$
$\therefore x = 100^o$

$Or$
Since, Exterior angle$=$Sum of interior opposite angles, therefore $x=50^o+50^o=110^o$.

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