Mathematics

If $AD$ is internal angle bisector of $\angle BAC, BD : DC = 2:3$, then find $AC : AB$.

SOLUTION
Given that:
$BD:DC=2:3$ and $AD$ is internal angle bisector of $\angle BAC.$
By Angle Bisector Theorem,
$\cfrac{BD}{DC}=\cfrac{AB}{AC}$
$\Rightarrow \cfrac{AB}{AC}=\cfrac23$
$\Rightarrow \cfrac{AC}{AB}=\cfrac32$ You're just one step away

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