Mathematics

If an angle is $$60^o$$ less than two times of its supplement, then the greater angle is 


ANSWER

$$100^o$$


SOLUTION
Option (a) is correct.
Let an angle be $$x$$ and $$180^o-x$$ be supplementary angles.
So, according to question,
$$\Rightarrow x=2(180^o -x)-60^o$$
$$\Rightarrow  x=360^o -2x-60^o$$
$$\Rightarrow x+2x=300^o$$
$$\Rightarrow 3x=300^o$$
$$\Rightarrow x=\dfrac{300^o}{3}$$
$$\Rightarrow x=100^o$$
$$\Rightarrow 180^0-x=80^0$$
Greater angle $$=100^0$$
Hence, option $$A$$ is correct
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