Mathematics

If an angle is $60^o$ less than two times of its supplement, then the greater angle is

$100^o$

SOLUTION
Option (a) is correct.
Let an angle be $x$ and $180^o-x$ be supplementary angles.
So, according to question,
$\Rightarrow x=2(180^o -x)-60^o$
$\Rightarrow x=360^o -2x-60^o$
$\Rightarrow x+2x=300^o$
$\Rightarrow 3x=300^o$
$\Rightarrow x=\dfrac{300^o}{3}$
$\Rightarrow x=100^o$
$\Rightarrow 180^0-x=80^0$
Greater angle $=100^0$
Hence, option $A$ is correct

You're just one step away

Single Correct Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
Enrolled Students 86

Realted Questions

Q1 Subjective Medium
Classify the angles whose magnitudes are given below:
$91^{o}$

Asked in: Mathematics - Lines and Angles

1 Verified Answer | Published on 09th 09, 2020

Q2 Subjective Medium
Make a pair of angles forming linear pair from the following angles:
$27^{\circ}, 90^{\circ}, 130^{\circ}, 80^{\circ}, 35^{\circ}, 50^{\circ}, 145^{\circ}, 100^{\circ}, 90^{\circ}, 153^{\circ}$.

Asked in: Mathematics - Lines and Angles

1 Verified Answer | Published on 09th 09, 2020

Q3 Subjective Medium
Identify whether the following pairs of angles are complementary or supplementary:
$63^o, 27^o$

Asked in: Mathematics - Lines and Angles

1 Verified Answer | Published on 09th 09, 2020

Q4 Subjective Hard
If a transversal intersects two lines such that the bisectors of a pair of corresponding angles are parallel, then prove that the two lines are parallel.

Asked in: Mathematics - Lines and Angles

1 Verified Answer | Published on 23rd 09, 2020

Q5 Single Correct Medium
$\displaystyle \angle AOF={ 120 }^{ o },\angle BOF={ 60 }^{ o }$ and $\angle BOD={ 90 }^{ o }$
Then find the unknown angles in the figure, where AB,CD and EF are straight lines intersecting at O.
• A. $\displaystyle \angle COF={ 90 }^{ o },\angle COA={ 90 }^{ o },\angle AOE={ 60 }^{ o },\angle EOD={ 60 }^{ o }$
• B. $\displaystyle \angle COF={ 60 }^{ o },\angle COA={ 60 }^{ o },\angle AOE={ 90 }^{ o },\angle EOD={ 90 }^{ o }$
• C. $\displaystyle \angle COF={ 30 }^{ o },\angle COA={ 30 }^{ o },\angle AOE={ 60 }^{ o },\angle EOD={ 30 }^{ o }$
• D. $\displaystyle \angle COF={ 30 }^{ o },\angle COA={ 90 }^{ o },\angle AOE={ 60 }^{ o },\angle EOD={ 30 }^{ o }$

Asked in: Mathematics - Lines and Angles

1 Verified Answer | Published on 09th 09, 2020