Mathematics

# If an angle is $60^o$ less than two times of its supplement, then the greater angle is

$100^o$

##### SOLUTION
Option (a) is correct.
Let an angle be $x$ and $180^o-x$ be supplementary angles.
So, according to question,
$\Rightarrow x=2(180^o -x)-60^o$
$\Rightarrow x=360^o -2x-60^o$
$\Rightarrow x+2x=300^o$
$\Rightarrow 3x=300^o$
$\Rightarrow x=\dfrac{300^o}{3}$
$\Rightarrow x=100^o$
$\Rightarrow 180^0-x=80^0$
Greater angle $=100^0$
Hence, option $A$ is correct

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Single Correct Medium Published on 09th 09, 2020
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