Physics

# If $C$ is the capacity, $V$ is the potential difference, the energy stored in a capacitor is given by $E=\dfrac { 1 }{ 2 } { CV }^{ 2 }$. The dimension of time in ${ CV }^{ 2 }$ is:

$-2$

##### SOLUTION
As we know energy stored inside the capacitor is $\dfrac{1}{2}cv^2$.
${cv}^2$ will have dimensions of energy only, i.e.,$ML^2T^{-2}$
Hence, option A is correct.

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Single Correct Medium Published on 18th 08, 2020
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