Physics

# If F is the force, S is the displacement and V is the velocity of the particle, the dimensions of the ratio $F S/{ V }^{ 2 }$ will be

${ M }\quad { L }^{ o }\quad { T }^{ o }$

##### SOLUTION
The dimensions of the force is $F=MLT^{-2}$

Since S is the displacement. so, it has dimensions $S=[L]$

The dimensions of the velocity is $V=[LT^{-1}]$

$\dfrac{FS}{V^2}=\dfrac{ML^2T^{-2}}{L^2T^{-2}}=ML^0T^0$

Option $\textbf B$ is the correct answer

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Single Correct Medium Published on 18th 08, 2020
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