Physics

If $${ (force) }^{ x }=\dfrac { \left( Mass \right) ^{ 2 }\left( radius \right) ^{ 2 } }{ \left( time \ period \right) ^{ 4 } } $$, then the value of $$x$$ is


ANSWER

2


SOLUTION

$$(force)^{x}=\dfrac{(Mass)^{2}(radius)^{2}}{p^{4}}$$

$$(M^{1}L^{1}T^{-2})^{x}=$$$$M^{2}L^{2}T^{-4}$$ 

$$\Rightarrow x=2$$

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