Physics

# If ${ (force) }^{ x }=\dfrac { \left( Mass \right) ^{ 2 }\left( radius \right) ^{ 2 } }{ \left( time \ period \right) ^{ 4 } }$, then the value of $x$ is

2

##### SOLUTION

$(force)^{x}=\dfrac{(Mass)^{2}(radius)^{2}}{p^{4}}$

$(M^{1}L^{1}T^{-2})^{x}=$$M^{2}L^{2}T^{-4}$

$\Rightarrow x=2$

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Single Correct Medium Published on 18th 08, 2020
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