Physics

If $$L$$ has the dimensions of length, $$V$$ that of potential and $${ \epsilon}_{0}$$ is the permittivity of free space then quantity $$LV$$$${ \epsilon}_{0}$$ has the dimensions of:


ANSWER

charge


SOLUTION
$$L \rightarrow  M^{0}L^{1}T^{0}$$
$$V \rightarrow ML^{2}I^{-1}T^{-3}$$
$$\epsilon_{0} \rightarrow M^{-1} L^{-3} I^{2}T^{4}$$
$$LV \epsilon_{0} \rightarrow M^{0} L^{0} I^{1}T^{1}$$
Charge $$\rightarrow M^{0}L^{0}I^{1}T^{1}$$
Hence, $$LV\epsilon_{0}$$ has dimension of charge.
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