Physics

# If $L$ has the dimensions of length, $V$ that of potential and ${ \epsilon}_{0}$ is the permittivity of free space then quantity $LV$${ \epsilon}_{0}$ has the dimensions of:

charge

##### SOLUTION
$L \rightarrow M^{0}L^{1}T^{0}$
$V \rightarrow ML^{2}I^{-1}T^{-3}$
$\epsilon_{0} \rightarrow M^{-1} L^{-3} I^{2}T^{4}$
$LV \epsilon_{0} \rightarrow M^{0} L^{0} I^{1}T^{1}$
Charge $\rightarrow M^{0}L^{0}I^{1}T^{1}$
Hence, $LV\epsilon_{0}$ has dimension of charge.

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Single Correct Medium Published on 18th 08, 2020
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