Physics

# If $L=(20+pm 0.01)m$ and $B=(10\pm 0.02)m$ then $L/B$ is

$(2\pm 0.01)m$

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Single Correct Medium Published on 18th 08, 2020
Questions 244531
Subjects 8
Chapters 125
Enrolled Students 199

#### Realted Questions

Q1 Single Correct Medium
Two resistances are expressed as $R_{ 1 }(4\pm$ 0.5 %)$\Omega$ and $R_{2}(12\pm$ 0.5 %)$\Omega$. The net resistance when they are connected in series with percentage error is:
(In series  $R = R_{1} + R_{2}$)
• A. $(16\pm$ 0.5 %) $\Omega$
• B. $(16\pm$ 6.25 %) $\Omega$
• C. $(16\pm$ 22 %) $\Omega$
• D. $(16\pm$ 2.2 %) $\Omega$

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q2 Single Correct Medium
Arrange the following physical quantities in the increasing order of their magnitudes
I.  $1\ dyne$
II.  $1 N$
III.  $3 kg \ m \ s^{-2}$

IV. ${ 10 }^{ 7 } g \ cm \ { s }^{ -2 }$
• A. II, I, III, IV
• B. IV, I, III, II
• C. II, III, I, IV
• D. I, II, III, IV

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q3 Single Correct Medium
When 97.52 is divided by 2.54, the correct result is :
• A. 38.3937
• B. 38.394
• C. 38.39
• D. 38.4

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q4 Single Correct Medium
The specific resistance $\rho$ of a circular wire of radius r, resistance R, and length l is given by $\rho = \pi r^2 R/l$. Given: $r = 0.24\pm 0.02 cm, R = 30 \pm 1 \Omega,$ and $l=4.80\pm 0.01cm.$ The percentage error in $\rho$ is nearly:
• A. $7\%$
• B. $9\%$
• C. $13\%$
• D. $20\%$

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020

Q5 Single Correct Medium
From the following combination of physical constant (expressed though their usual symbols) the only combination, that would have the same value in different systems of units is:
• A. $\dfrac{ch}{2\pi \varepsilon_0^2}$
• B. $\dfrac{e^2}{2\pi \varepsilon_0 Gm_e^2}(m_e = mass \,of \,electron)$
• C. $\dfrac{\mu_0 \varepsilon_0}{c^2} \dfrac{G}{he^2}$
• D. $\dfrac{2\pi\sqrt{\mu_0\varepsilon_0}h}{c^2e^2}\dfrac{h}{G}$

Asked in: Physics - Units and Measurement

1 Verified Answer | Published on 18th 08, 2020