Physics

If '$$R$$' is Rydberg constant, '$$h$$' is Planck's constant, '$$c$$' is velocity of light, then '$$Rhc$$' has the same dimensional formula as that of


ANSWER

Energy


SOLUTION
$$R=M^{0}L^{-1}T^{0}$$
$$h=\dfrac{Energy}{c/\lambda }=\dfrac{M^{1}L^{2}T^{-2}}{LT^{-1}L^{-1}}=M^{1}L^{2}T^{-1}$$
$$c=LT^{-1}$$
Therefore, $$ Rhc=M{ L }^{ 2 }{ T }^{ -2 }$$
Energy 
$$=M^{1}L^{2}T^{-2}$$,
Force $$=M^{1}L^{1}T^{-2}$$
Angular momentum $$=M^{1}L^{2}T^{-1}$$ 
Power $$=M^{1}L^{2}T^{-3}$$
Hence, option A is correct.
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