Physics

# If '$R$' is Rydberg constant, '$h$' is Planck's constant, '$c$' is velocity of light, then '$Rhc$' has the same dimensional formula as that of

Energy

##### SOLUTION
$R=M^{0}L^{-1}T^{0}$
$h=\dfrac{Energy}{c/\lambda }=\dfrac{M^{1}L^{2}T^{-2}}{LT^{-1}L^{-1}}=M^{1}L^{2}T^{-1}$
$c=LT^{-1}$
Therefore, $Rhc=M{ L }^{ 2 }{ T }^{ -2 }$
Energy
$=M^{1}L^{2}T^{-2}$,
Force $=M^{1}L^{1}T^{-2}$
Angular momentum $=M^{1}L^{2}T^{-1}$
Power $=M^{1}L^{2}T^{-3}$
Hence, option A is correct.

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Single Correct Medium Published on 18th 08, 2020
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