Mathematics

If the complement of an angle is $$79^o$$, then the angle will be of 


ANSWER

$$11^o$$


SOLUTION
Let, $$y$$ be the angle
Then, complement angle $$=90^o -y$$
Now, according to the question 
$$ 90^o -y=79^o\quad$$[Given]
$$\Rightarrow y=90^o -79^o$$
$$=y=11^o$$

$$\therefore 11^o$$ is the required angle.
Hence, option (B) is correct.
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