Mathematics

If the complement of an angle is $79^o$, then the angle will be of

$11^o$

SOLUTION
Let, $y$ be the angle
Then, complement angle $=90^o -y$
Now, according to the question
$90^o -y=79^o\quad$[Given]
$\Rightarrow y=90^o -79^o$
$=y=11^o$

$\therefore 11^o$ is the required angle.
Hence, option (B) is correct.

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Single Correct Medium Published on 09th 09, 2020
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