Mathematics

If the difference of two supplementary angles is $${ 40 }^{ o }$$, then the measurement of the greater angle is


ANSWER

$${ 110 }^{ o }$$


SOLUTION
let one anngle be $$x$$
The other supplementary angle is $$180^0 -x$$
$$ So,$$
$$ 180-x-x=40$$
$$\implies\quad 180-2x=40$$
$$\implies\quad 2x=180-40$$
$$\implies\quad x=70$$
$$\implies\quad 180-x={ 110 }^{ \circ  }$$
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