Physics

# If the displacement S of a body in time '$t$' is given by $S={ At }^{ 3 }+{ Bt }^{ 2 }+Ct+D$, the dimension of A is:

${ L }^{ 1 }{ T }^{ -3 }$

##### SOLUTION

$S=At^{3}+Bt^{2}+(t+1)$

$L^{1}=At^{3}$

$A=LT^{-3}$

$L^{1}=Bt^{2}\Rightarrow B=LT^{-2}$

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Single Correct Medium Published on 18th 08, 2020
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