Physics

# If the error in measurements of mass and velocity is 1% each then error in measurement of kinetic energy is:

##### SOLUTION

Kinetic energy is $K=\dfrac{1}{2}m{{v}^{2}}$

Percentage error in kinetic energy

$=\left( \dfrac{\Delta m}{m}+\dfrac{2\Delta v}{v} \right)\times 100$

$=\left( 0.01+2(0.01) \right)\times 100$

$=0.03\times 100$

$=3\,$%

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Subjective Medium Published on 18th 08, 2020
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