Physics

If the force is given by $F$ = $at+bt^2$ with $t$ as time. The dimensions of a and b are:

$[MLT^{-3}], [MLT^{-4}]$

SOLUTION
Dimension of force F : $[MLT^{-2}]$
$F=at+bt^2$
$\implies$ Dimension of $a:[MLT^{-2}]\times [T^{-1}]$$=[MLT^{-3}] Dimensions of b:[MLT^{-2}]\times [T^{-2}]$$=[MLT^{-4}]$

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Single Correct Medium Published on 18th 08, 2020
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