Physics

If the ratio of fundamental units in two systems is 1 :3, then the ratio of momentum in the two systems is:


ANSWER

1:3


SOLUTION
$$\displaystyle \Rightarrow \frac{M_{1}}{M_{2}}=\frac{1}{3}, \frac{L_{1}}{L_{2}}=\frac{1}{3}, \frac{T_{1}}{T_{2}}=\frac{1}{3}$$

$$\Rightarrow \displaystyle \frac{\left ( momentum \right )_{1}}{\left ( momentum \right )_{2}}$$=$$\dfrac{M_{1}^{1}L_{1}^{1}T_{1}^{-1}}{M_{2}^{1}L_{2}^{1}T_{2}^{-1}}=\dfrac{1}{3}\times \dfrac{1}{3}\times \left ( \dfrac{1}{3} \right )^{-1}=\dfrac{1}{3}$$
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