Physics

If $$y$$ represents pressure and $$x$$ represents velocity  gradient, then the dimensions of $$\dfrac { { d }^{ 2 }y }{ d{ x  }^{ 2 } }$$ are


ANSWER

$$\left[ ML^{ -1 }T^{ 0 } \right] $$


SOLUTION
Dimensions of $$\dfrac { { d }^{ 2 }y }{ d{ x }^{ 2 } } $$  = dimension of $$\dfrac { y }{ { x }^{ 2 } } $$
Dimension of y $$M{ L }^{ -1 }{ T }^{ -2 }$$
Dimension of x $${ T }^{ -1 }$$
$$\dfrac { { d }^{ 2 }y }{ d{ x }^{ 2 } } \quad =\dfrac { M{ L }^{ -1 }{ T }^{ -2 } }{ { \left( { T }^{ -1 } \right)  }^{ 2 } } \\ =M{ L }^{ -1 }{ T }^{ 0 }$$
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Single Correct Medium Published on 18th 08, 2020
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