Physics

# If $y$ represents the pressure and $x$ represents the position then dimensional expression of $\int { \dfrac { dx }{ \sqrt { p^{ 2 }- y^2} } }$

$[M^{-1}L^2T^{2}]$

##### SOLUTION
Dimension of pressure = $ML^{-1}T^{-2}$
Dimensions of p and y has to be equal
Dimensions of $dx = L^{1}$
$\therefore$ Dimensions of $\int { \dfrac { dx }{ \sqrt { p^2 - y^2 } } }$
Dimension of $\cfrac{dx}{y} = \cfrac{L^{1}}{ML^{-1}T^{-2}}$
$= M^{-1}L^2T^2$

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Single Correct Medium Published on 18th 08, 2020
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