Mathematics

In $\Delta ABC$, if $\angle A+\angle B=90^{\circ}$, cot $B=\dfrac{3}{4}$, then the value of tan A is :

$\dfrac{3}{4}$

SOLUTION
$\angle A+\angle B={ 90 }^{ \circ }\\ \angle B={ 90 }^{ \circ }-\angle A$
$\cot { B } =\dfrac { 3 }{ 4 } \\ \cot { \left( { 90 }^{ \circ }-\angle A \right) } =\dfrac { 3 }{ 4 } \\ \tan { A } =\dfrac { 3 }{ 4 }$

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Single Correct Medium Published on 09th 09, 2020
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