Mathematics

In fig. if $$AB || CD$$ then find the value of $$x$$.


SOLUTION
From the figure we have, $$\angle EPB=180^o-(5x-20^o)$$......(1)[ Since $$\angle BPE+\angle QPB=180^o$$]
Again $$\angle PQD=\angle QPB$$ [ Similar angles]
or, $$180^o-(5x-20^o)=2x-10^o$$
or, $$7x=210^o$$
or, $$x=\dfrac{210^o}{7}=30^o$$.
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