Mathematics

In fig. if $AB || CD$ then find the value of $x$.

SOLUTION
From the figure we have, $\angle EPB=180^o-(5x-20^o)$......(1)[ Since $\angle BPE+\angle QPB=180^o$]
Again $\angle PQD=\angle QPB$ [ Similar angles]
or, $180^o-(5x-20^o)=2x-10^o$
or, $7x=210^o$
or, $x=\dfrac{210^o}{7}=30^o$.

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Subjective Medium Published on 09th 09, 2020
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