Mathematics

In the given diagram CE is  parallel to AD and the measures of two angles at B and C have been indicated .Then $$\angle DAB $$  is equal to


ANSWER

$$40^{\circ}$$


SOLUTION
Since, CE || DA
$$\angle ECF =\angle DFB = 70$$

$$\angle DFB + \angle AFB = 180 $$(angles on a straight line)
thus, $$\angle AFB = 110$$

In $$\Delta AFB$$,
$$\angle AFB + \angle FBA + \angle BAF = 180$$
$$110 + 30 + \angle BAF = 180$$
$$\angle BAF = 180- 140$$
$$\angle BAF = 40^{\circ}$$
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