Mathematics

In the given figure, $\angle QPB$  is,

$30^{\circ}$

SOLUTION
In the given figure,
$\angle APR + \angle RPQ + \angle QPB = 180^{\circ}$
$2x + 3x+x = 180^{\circ}$
$6x = 180^{\circ}$
$x = 30^{\circ}$

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Single Correct Medium Published on 09th 09, 2020
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