Mathematics

In the given figure, $$\angle QPB$$  is,


ANSWER

$$30^{\circ}$$


SOLUTION
In the given figure,
$$\angle APR + \angle RPQ + \angle QPB = 180^{\circ}$$
$$2x + 3x+x = 180^{\circ}$$
$$6x = 180^{\circ}$$
$$x = 30^{\circ}$$
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