Mathematics

# In the given figure, $AOB$ is a straight line and the ray $OC$ stands on it. If $\angle BOC=132^{o}$, then $\angle AOC=?$

$48^{o}$

##### SOLUTION
$\angle AOC$ = ?
= $\angle AOC + \angle BOC$ = $180^{o}$....$[\because Linear\,pair]$
= $\angle AOC + 132^{o}$ = $180^{o}$
= $\angle AOC$ = $180^{o}-132^{o}$
$\angle AOC$ = $48^{o}$

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Single Correct Medium Published on 09th 09, 2020
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