Mathematics

In the given figure, $$AOB$$ is a straight line and the ray $$OC$$ stands on it. If $$\angle BOC=132^{o}$$, then $$\angle AOC=?$$


ANSWER

$$48^{o}$$


SOLUTION
$$\angle AOC$$ = ?
= $$\angle AOC + \angle BOC$$ = $$180^{o}$$....$$[\because Linear\,pair]$$
= $$\angle AOC + 132^{o}$$ = $$180^{o}$$
= $$\angle AOC$$ = $$180^{o}-132^{o}$$
$$\angle AOC$$ = $$48^{o}$$
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Single Correct Medium Published on 09th 09, 2020
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