Mathematics

# In the given figure, two lines $AB$ and $CD$ intersect at $O$. Ray $OE$ is perpendicular to the line $AB$. If $a:b=3:7,$ then find reflex $\angle BOD$.

##### SOLUTION
In the given figure,

We have,

$a:b=3:7$

$\angle EOA=90^o$

Let $a=3x , b=7x$

Since,
$\angle EOC+\angle BOC +\angle EOA=180^o$

$3x+7x+90^o=180^o$

$x=9^o$

Thus $a=27^o$ and $b=63^o$

Now,

$=\angle AOB+\angle BOD$

$=63^o+\angle BOD=180^o$

$=\angle BOD=117^o$

You're just one step away

Subjective Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
Enrolled Students 86

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