Mathematics

In $\triangle\ PQR,\angle\ Q=40^{o},\angle\ R=75^{o}$, then find the shortest and the longest side of the triangle

SOLUTION
$\longrightarrow \angle Q=40^o$
$\angle R=75^o$
$\therefore \angle P=180^o-(40^o+75^o)$
$\therefore \angle P=180-115$
$\therefore \angle P=65^o$
Side opposite to greatest angle is greatest and side opposite to shortest angle is shortest.
$\therefore$ side $PR$ is shortest
$\therefore$ side $PQ$ is longest You're just one step away

Subjective Medium Published on 09th 09, 2020
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