Mathematics

In $$\triangle\ PQR,\angle\ Q=40^{o},\angle\ R=75^{o}$$, then find the shortest and the longest side of the triangle


SOLUTION
$$\longrightarrow \angle Q=40^o$$
$$\angle R=75^o$$
$$\therefore \angle P=180^o-(40^o+75^o)$$
$$\therefore \angle P=180-115$$
$$\therefore \angle P=65^o$$
Side opposite to greatest angle is greatest and side opposite to shortest angle is shortest.
$$\therefore $$ side $$PR$$ is shortest
$$\therefore $$ side $$PQ$$ is longest
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