Physics

$$\left[ \dfrac { Permeability }{ Permittivity }  \right] $$will have the dimensions of :


ANSWER

$${ M }^{ 2 }{ L }^{ 4 }{ T }^{ -6 }{ A }^{ -4 }$$


SOLUTION
Permeability $$= \mu _{0} = M L A^{-2} T^{-2}$$ .........(1)
Permittivity $$= M^{-1} L^{-3} A^{2} T^{4}$$ .................(2)
So,  $$\dfrac{eq^{n}(1)}{eq^{n}(2)} = \dfrac{M  L A^{-2} T^{-2}}{M^{-1} L^{-3} A^{2} T^{4}} = M^{2} L^{+4} A^{-4} T^{-6}$$
Hence, option C is correct.
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Single Correct Medium Published on 18th 08, 2020
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