Mathematics

Mark the correct alternative of the following.In figure, PQ$||$RS and $\angle$PAB$=60^o$ and $\angle ACS=100^o$. Then, $\angle BAC=?$

$40^o$

SOLUTION
From the picture it is clear that $\angle PAC=\angle ACS$. [ Alternate angles]
So,
$\angle PAB+\angle BAC=\angle ACS$ [ Since $\angle PAC=\angle PAB+\angle BAC$]
or, $\angle BAC=100^0-60^o$
or, $\angle BAC=40^o$.

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Single Correct Medium Published on 09th 09, 2020
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