Mathematics

Mark the correct alternative of the following.
In figure, PQ$$||$$RS and $$\angle$$PAB$$=60^o$$ and $$\angle ACS=100^o$$. Then, $$\angle BAC=?$$


ANSWER

$$40^o$$


SOLUTION
From the picture it is clear that $$\angle PAC=\angle ACS$$. [ Alternate angles]
So,
$$\angle PAB+\angle BAC=\angle ACS$$ [ Since $$\angle PAC=\angle PAB+\angle BAC$$]
or, $$\angle BAC=100^0-60^o$$
or, $$\angle BAC=40^o$$.
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