Physics

# Modulus of Elasticity is dimensionally equivalent to:

Stress

##### SOLUTION
Modulus of elasticity $=M^{1}L^{-1}T^{-2}$
Stress $=M^{1}L^{-1}T^{-2}$
Surface tension $=\dfrac{f}{l}=M^{1}L^{0}T^{-2}$
Strain
$=\dfrac{\Delta L}{L}=M^{0}L^{0}T^{0}$
Coeff of viscosity$=F/A\dfrac{dv_{x}}{dx}=\dfrac{MLT^{-2}}{L^{2}\dfrac{LT^{-1}}{L}}=ML^{-1}T^{-1}$
Hence, option A is correct.

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Single Correct Medium Published on 18th 08, 2020
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