Passage

Ray PR and ray PQ are perpendicular to each other. The point B is in the interior of $$\angle QPR$$ and a point A is in the exterior of $$\angle RPQ$$ such that ray PB and ray PA are perpendicular to each other. Draw the figure and write down the number of pairs of:
Mathematics

Congruent angles


ANSWER

2


SOLUTION
The pair of Congruent angles are:
$$1.\angle QPR \equiv \angle BPA$$ [each angle is $$90^0$$]
$$2. \angle QPR = \angle BPA$$ [as given]
$$ \angle QPB +\angle BPR=\angle BPR+\angle RPA$$ [using addition property]
so, $$ \angle QPB = \angle RPA$$
i.e. $$2$$ pairs.
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One Word Medium Published on 09th 09, 2020
Mathematics

Supplementary angles


ANSWER

1


SOLUTION
The pair of Supplementary angles is:
$$1. \angle QPR +\angle BPA=180^0$$ [as both are given as $$90^0$$]
$$1$$ pair.
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One Word Medium Published on 09th 09, 2020
Mathematics

Complementary angles


ANSWER

2


SOLUTION
The pairs pf Complementary angles are:
$$1.$$ $$\angle RPB + \angle BPQ=90^0$$
$$2.$$ $$\angle BPR+\angle RPA=90^0$$
Hence there are $$2$$ pairs of complementary angles.
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