Mathematics

State True or FalseFrom the following figure, we can say:  $\angle ACD= \angle CBE$

True

SOLUTION
In $\triangle$ ABC,
AB = AC
thus, $\angle ABC = \angle ACB = x$ (Opposite angles of equal sides are equal)
Now, $\angle ABC + \angle CBE = 180$ (Angles on a straight line)
$x + \angle CBE = 180$
$\angle CBE = 180 - x$ (I)
Also, $\angle ACB + \angle ACD = 180$ (Angles on a straight line)
$x + \angle ACD = 180$
$\angle ACD = 180 - x$ (II)
Hence, from I and II
$\angle ACD = \angle CBE$

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TRUE/FALSE Medium Published on 09th 09, 2020
Questions 120418
Subjects 10
Chapters 88
Enrolled Students 86

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