Mathematics

The complement of $0^o$ is

${90^ \circ }$

SOLUTION
Complement of any angle$\theta$ is ${90}^{\circ}-\theta$
$\therefore\,$Complement of ${0}^{\circ}$ is ${90}^{\circ}-{0}^{\circ}={90}^{\circ}$

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Single Correct Medium Published on 09th 09, 2020
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