Mathematics

The complement of $$80^{o}$$ is


ANSWER

$$10^{o}$$


SOLUTION
Two angles are said to be complementary if the sum of their measures is $$90^{o}$$.
The given angle is $$80^{o}$$
Let the measure of its supplement be $$X^{o}$$.
Then,
$$\implies X^{o}+80^{o}=90^{o}$$
$$\implies X=90-80$$
$$\implies X=10$$
Hence, the supplement of the given angle measures $$10^{o}$$.
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