Mathematics

The complement of $80^{o}$ is

$10^{o}$

SOLUTION
Two angles are said to be complementary if the sum of their measures is $90^{o}$.
The given angle is $80^{o}$
Let the measure of its supplement be $X^{o}$.
Then,
$\implies X^{o}+80^{o}=90^{o}$
$\implies X=90-80$
$\implies X=10$
Hence, the supplement of the given angle measures $10^{o}$.

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Single Correct Medium Published on 09th 09, 2020
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