Mathematics

The difference between two supplementary angles is $$100^o$$. Then find the angles.


SOLUTION
Given the difference between two supplementary angles is $$100^o$$.

Let the angles be $$x$$ and $$y$$.

Then according to the problem,

$$x+y=180^o$$......(1) and $$x-y=100^o$$.....(2).

Now,Add (1) and (2) we get,

$$2x=280^o$$

$$x=140^o$$ 

substitute in $$(1)$$

$$y=180^o-140^o$$

$$y=40^o$$.
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