Physics

# The dimensional formula for Reynold's number is ________.

$[L^0M^0T^0]$

##### SOLUTION
The formula for Reynold's number is:
$Re=\dfrac { \rho vd }{ \mu } \\ \Rightarrow [Re]=\dfrac { [\rho ][v][d] }{ [\mu ] } =\dfrac { [M{ L }^{ -3 }][L{ T }^{ -1 }][L] }{ [{ ML }^{ -1 }{ T }^{ -1 }] } =[{ M }^{ 0 }{ L }^{ 0 }{ T }^{ 0 }]$.
Thus, Reynold's number is a dimensionless quantity. It is defined as the ratio of inertial force to viscous force, so it has to be a dimensionless number.

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Single Correct Medium Published on 18th 08, 2020
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