Physics

The dimensional formula for Reynold's number is ________.


ANSWER

$$[L^0M^0T^0]$$


SOLUTION
The formula for Reynold's number is: 
$$Re=\dfrac { \rho vd }{ \mu  } \\ \Rightarrow [Re]=\dfrac { [\rho ][v][d] }{ [\mu ] } =\dfrac { [M{ L }^{ -3 }][L{ T }^{ -1 }][L] }{ [{ ML }^{ -1 }{ T }^{ -1 }] } =[{ M }^{ 0 }{ L }^{ 0 }{ T }^{ 0 }]$$.
Thus, Reynold's number is a dimensionless quantity. It is defined as the ratio of inertial force to viscous force, so it has to be a dimensionless number.
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