Physics

# The dimensions of a modulus of elasticity are:

[$ML^{-1}T^{-2}$]

##### SOLUTION

Young modulus, $\gamma =\dfrac{stress}{strain}=\dfrac{Force\,/\,Area}{\Delta L/L}=\dfrac{\left[ ML{{T}^{-2}} \right]/\,\left[ {{M}^{o}}{{L}^{2}}{{T}^{o}} \right]}{\left[ {{M}^{o}}L{{T}^{o}} \right]/\left[ {{M}^{o}}L{{T}^{o}} \right]}=\left[ M{{L}^{-1}}{{T}^{-2}} \right]$

Hence, Dimension is $\left[ M{{L}^{-1}}{{T}^{-2}} \right]$ .

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Single Correct Medium Published on 18th 08, 2020
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