Physics

The dimensions of emf in MKS is:


ANSWER

$${ML^{2}}{T^{-2}}{Q^{-1}}$$


SOLUTION
The emf across an inductor is given by:
$$ e = -L\dfrac {di}{dt} $$

$$e = \big[ {ML^{2}}{T^{-2}}{A^{-2}} \big] \big[ \dfrac {A}{T} \big] $$

$$e = \dfrac {{ML^{2}}{T^{-2}}}{A^{-1}{T}} $$

$$e = {ML^{2}}{T^{-2}}{Q^{-1}}$$
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